How do you solve 3sinθtanθ + 2tanθ = 0?

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Crimson.Red -Sometimes you have to look at these from different angles (pardon the pun) to see a possible solution.I suggest changing tan to sin/cos like this:3sinθsinθ/cosθ + 2sinθ/cosθ = 0[3(sinθ)^2]/cosθ + 2sinθ/cosθ = 0Now, this will only equal zero if the numerator = 03(sinθ)^2 + 2sinθ = 0, now factor:sinθ(3sinθ +2) = 0So, just solve these two factors for zero:sinθ = 03sinθ +2 = 0I'll leave it for you to complete.Hope that helps