a ship fires its gun with a speed of 400 m/s at an angle  of 35 degree with the horizontal. fing the range and maximum altitude.

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Assuming no air friction, the horizontal velocity stays constant at VHor = 400 cos(35) = 327.7 m/s.   The range will be (VHor)(time flight) Time flight is dependent on the VVert = 400Sin(35) = 229.4 m/s.  Time up = VVert / g = 229.4 / 9.81 = 23.39 s.    Time flight = 2(time up) = 46.77 s Thus the height = [(VVo + VVf) / 2](time up) = (229.4 /2)(23.39) = 2682.8 m The range = (327.7 m/s)(46.77 s) = 15326.3 m