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f'(x) for f(x) = 0.8x^4

mark458

by mark458 at April 21, 2010

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what in the world is f'(x)in this integration?then its going to be 0.8/5 times x^5 =0.16 x^5or is this differentiation?then its going to be  0.8 x 4 times x^3 = 3.2 x^3

Sandesh Sandesh April 21, 2010

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