first you can factor the denominator of the first term so that you have:(x^2+4)/[(x+2)*(x-2)] - x/(x-2) = 2/(x+2)Then multiply everthing by the least common denominator: (x+2)*(x-2) This will cancel all the denominators of all the terms.x^2 + 4 - x*(x+2) = 2*(x-2) (distribute)x^2 + 4 - x^2 - 2x = 2x - 4 (cancel x^2's)4 - 2x = 2x - 4 (add 4 and add 2x to each side)8 = 4x (divide by 4 to get x alone)2 = x
Oh, and... very important point that I forgot. x does not equal 2 or -2 because that would make the denominators in the beginning 0, and we can't divide by 0. So.. since the answer was 2, there is no solution.
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