f(x)=x^2+xfind even or odd or neither even nor oddand draw it's graph

⚑ Flag

First, plug -x into the function to see if you get the same function or the negative of it:f(-x) = (-x)^2 + (-x)        = x^2 - x Since this is not f(x) and it's not -f(x) = -(x^2) -x, the function is neither even nor odd.To graph it find the zeros:  f(x) = x(x+1), the zeros are x = 0 and -1. And the vertex of the parabola is at x = -1/2.  (because of the -b/2a rule).  So when x = -1/2, y = -1/2*(1/2) = -1/4.So plot (-1/2, -1/4), (-1, 0), and (0, 0), and then connect in a parabola shape. :-)A brightstorm video you can watch about even and odd functions that might make it clearer:http://www.brightstorm.com/d/math/s/precalculus/u/introduction-to-functions/t/symmetry-of-graphs-odd-and-even-functionsAnd another video in case graphing the parabola was confusing:http://www.brightstorm.com/d/math/s/algebra-2/u/quadratic-equations-and-inequalities/t/finding-the-vertex-of-a-parabola-by-completing-the...