ok and what about this one?triangle abc withangle A = 53.1side a = 10side c = 14at first I thought of subtracting 53.1 from either 180 or 90 but I wasn't sure

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If your setup of triangle abc is the same as in the concept video, with angle A across from side a, then we know that sin(A)/a = sin(C)/c  which is the same as:sin(53.1)/10 = sin(C)/14      multiply 14 across(7/5)*sin(53.1) = sin(C)    take arcsin of both sidesarcsin((7/5)*sin(53.1)) = C    we can plug this into our calculator, and then we have angle C.  From there we simply subtract A and C from 180 to get angle B, and then use the same methods I used above to find side b.