how do you write an equation in standard form when given the point and a slope

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Solve for y = mx + b or y - y1 = m (m - x1). Your line will be in slope intercept form. Now add/subtract/multiply/divide in order to get to Ax + By = C, where A,B&C are non-fractions and A>0. For example: Write the equation of a line in standard form that has a slope of 4 and passes through (-3,5). y - y1 = m (x - x1) y - 5 = 4 (x - (-3)) y - 5 = 4x + 12 Add 5 to both sides. y = 4x + 17 Subtract 4x from both sides to get the variables on the same side. -4x + y = 17 The pattern for Standard Form shows that the coefficient with x can't be negative when it expresses A>0. So, multiply everything by -1, keeping in mind you can do anything to an equation and it will remain true as long as you do it to both sides. -1(-4x + y = 17) 4x - y = -17