ln(x+5) = ln(x-1)-ln(x+1) 

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Hmm I'll briefly show you the step by step process. ln(x+5) = ln(x-1) - ln(x+1) ln (x+5) = ln(x-1)/(x+1) x+5 = (x-1)/(x+1) x^2 + x + 5x + 5 = x - 1 x^2 + 6x + 5 = x - 1 x^2 + 6x + 5 - x + 1 = 0 x^2 + 5x + 6 = 0 (x + 5)(x+1) = 0 x = -5 or -1